E and F are the mid-points of the sides AB and AC of a AABC. If AB = 6cm, BC = 5cm and AC = 6cm, Then EF is equal to
Answers
Answer:
2.5cm
Step-by-step explanation:
It's an isosceles triangle where AB = AC and E, F are midpoint
so, AE,EB,AF,FC all are of 3 cm
According to Similar triangle property,
Common angle A, hence
AE/AB=AF/AC=EF/BC
SO, 3/6=1/2=EF/5
Hence, EF = 2.5 cm
Answer:
The length of EF is equal to 2.5 cm.
Step-by-step explanation:
Given,
ABC is a triangle that has E and F midpoints of the sides AB and AC,
i.e., E is the midpoint of AB and F is the midpoint of AC.
The length of AB = 6 cm
The length of BC = 5 cm
and, the length of AC = 6 cm
As E is the midpoint, so AE = BE = (1/2)AB = (1/2)×6 = 3 cm
As F is the midpoint, so AF = CF = (1/2)AC = (1/2)×6 = 3 cm
Using the midpoint theorem,
EF || BC, so EF = (1/2)×BC = (1/2)×5 = 2.5 cm
Hence, the length of EF is 2.5 cm.
To know more about the triangle, click on the link below:
https://brainly.in/question/325089
To know more about the midpoint theorem, click on the link below:
https://brainly.in/question/2609167
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