E and f can separately do a piece of work in 40 and 30 days respectively. They worked together for 12 days, after which f was replaced by g, if the works was finished in next 8 days, then the number of days in which g alone could do the work will be.
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Answer:
80 days
Step-by-step explanation:
E & F can complete work in 1 day equal to 1/40 + 1/30 = 7/120
In 12 days, part of work completed = 12 * 7/120 = 7/10 part.
Remaining part of work to be completed = 3/10.
3/10 part of work ===> 8 days
whole work can be done in = 1/3/10 *8 = 80/3 days.
So E&G together can complete the work in 80/3 days.
E&G can together complete work in 1 day is 1/40 + 1/G = 3/80
=> 1/G = 3/80 - 1/40 = 1/80 days.
G alone can do the work in 80 days.
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