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1. a+b+c=0 then A³+b³+c³=
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Answer:
a +b +c = 0
a^3+b^3+c^3-3abc = (a +b +c)(a^2+b^2+c^2 -ab-bc-ca)
a^3+b^3+c^3 -3abc = (0)(a^2+b^2+c^2 -ab-bc-ca)
a^3+b^3+c^3 -3abc = 0
a^3+b^3+c^3 = 3abc
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