Question

e) As age is 4 times that of B's age. 10 years ago, A's age was 19 times that of B's age. Find the
present ages of A and B.​

Answer 1

Answer:

let the present age of B=x and A's age =4x

10 years ago ,

A 's age=4x-10

B 's age= x-10

A. T. Q.,

19(x-10)=4x-10

$19x - 190 = 4x - 10 \\ 19x - 4x \: \: = - 10 + 190 \\ 15x = 180 \\ x = \frac{180}{15} = 12$

HENCE, A' age =4*12=48 years

N' age =12 years