Question

E
Car
Normal daughter
Nommal son
CASE 3
colour
-cross
Think of a possibility of a marriage between
carrier woman (XX°) and a colour blind man
(XºY). Is there a possibility of the birth of a colour
blind daughter ? Work out the progeny in the
following Punnett square.
Colour-blind man (XⓇY)
sperms (two types)
ale
THER
on
Carrier woman (XºX)
Eggs (two types)
29​

Answer 1

yes , if a carrier women is crossed with a color blind male......there is color blind daughter, and also a carrier daughter.

Answer:

$\left[\begin{array}{ccc}-&X^R&Y\\X&XX^R&XY\\X^o&X^oX^R&X^oY\end{array}\right]$

Explanation:

  if a carrier women is crossed with a color blind male:

     the progeny produced are

1. carrier female($XX^R$)

2. color blind female($X^oX^R$)

3. normal male($XY$) and

4. color blind male($X^oY$).