E D EXAMPLE 13. In the given figure, AB is a line segment and Pis its mid point. D and E are points on the same side of AB such that A B BAD = LABE and < EPA = Z DPB.
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Answer:
It is given that ∠EPA=∠DPB
Now,
∠EPA+∠DPE=∠DPB+∠DPE
Therefore,
∠DPA=∠EPB
In ΔEBP and ΔDAP,
∠EBP=∠DAP (given)
BP=AP (P is midpoint of AB)
∠EPB=∠DPA [proved above]
By ASA criterion of congruence,
ΔEBP≅ΔDAP
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Answer:
the answer is 450x y i think
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