Question

E distance between Point (x
,3) cand (5,7).
is 5 them find value of x​

Answer 1

Answer:

Let P(x, 3) and Q(5,7)

PQ = √(x2 - x1)² + (y2 - y1)²

5 = √(5 - x)² + (7 - 3)²

= √x² - 10x + 41

Squaring both sides,

x² - 10x + 41 = 25

x² - 10x + 16 = 0

By factorization,

x² - 2x - 8x + 16 = 0

x(x - 2) -8(x - 2) = 0

(x - 2) (x - 8) = 0

x = 2 OR x = 8

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