Question

e. find the electrie field intensity at axial position
of an electric dipole a distances of 30cm and electric dipole moment is given 10Cm​

Answer 1

Given ,

Distance (r) = 30 cm or 0.3 m

Dipole moment (P) = 10 C-m

We know that , the electric field due to electric dipole at a axial point is given by

$\boxed{ \tt{E = \frac{2KP}{ {(r)}^{3} } }}$

Thus ,

$\tt \implies E = \frac{2 \times 9 \times {(10)}^{9} \times 10 }{ {(0.3)}^{3} }$

$\tt \implies E = \frac{18 \times {(10)}^{10} }{0.027}$

$\tt \implies E = \frac{18 \times {(10)}^{13} }{27}$

$\tt \implies E = 0.6 \times {(10)}^{13} \: \: N/C$

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