Question

e) Find the point on the curve y=3x-x^2 at which slope is -5.​

Answer 1

Answer:

It's too easy

Step-by-step explanation:

Check the attachment for your answer

Answer 2

Answer:

The point on the curve is (4, -4)

Step-by-step explanation:

The slope of a curve at a given point is equal to the slope of the tangent line drawn at that point.

To find the slope of the curve at a given point, differentiate the equation of the curve and the first derivation of the curve that is  $\frac{dy}{dx}$

Given the equation of the curve is $y=3x-x^{2}$

To find the slope of the equation differentiate the above equation.

$\frac{dy}{dx} =3-2x$

Given that the slope is 5

Therefore,

$5 = 3 - 2x$

$x = 4$

Substitute x in the given equation

$y = 3(4)-4^{2}$

$y = 16$

Therefore the point on the curve is (4, -4)