Question

e for x if: tan (180°-6). tan (90°+0)+x cos (90°+0). cos (90°-O)=sin 0. sin (180°-0) ​

Answer 1

Answer:

Step-by-step explanation:

Given xcot(90+θ)+tan(90+θ)sinθ+csc(90+θ)=0

x=−tan(90+θ)(tan(90+θ)sinθ+csc(90+θ))

x=cotθ(−cosθ+secθ)

x=cotθ(sin  

2

θ/cosθ)=sinθ

Hence x=sinθ