Question

e.g., y = cos ( log (tan (e^x)))

please help to differentiate it ..



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Answer 1

Answer:

thank

HOPE IT HELPS YOU ☺️

Answer 2

Answer:

{-sin[log(tan(e^x))] . 1/tan(e^x) . sec^2e^x . e^x}

Explanation: we have to use chain rule method here.

question: cos(log(tan(e^X))).

step-1: first of all we have cos if we differentiate cosx we will get -sinx.

therefore {-sin[log(tan(e^x))]}.

step-2: second we now have differentiated cos now nest is log and as we know differentiation of logx =1/x therefore {-sin[log(tan(e^x))] . 1/tan(e^x)}.

step-3: third now we have left with tan(e^x) ,differentiation of tanx =sec^2x

therefore {-sin[log(tan(e^x))] . 1/tan(e^x) . sec^2(e^x)}.

step-4: fourth now we have left with only e^x whose differentiation is e^x only therefore our final answer is {-sin[log(tan(e^x))] . 1/tan(e^x) . sec^2(e^x)  . e^x}.