Question

e) In the adjoining figure, triangles AMB and ANB
are standing on the same base AB and between
the same parallel lines AB and MN, Prove that
area of A AOM = area of ABON.
0
A​

Answer 1

Answer:

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Step-by-step explanation:

Solved example for the triangle and parallelogram on same base and between same parallels:

1. ∆ ABD and parallelogram ABCD are on the same base AB. If base and altitude of the parallelogram are 15 cm and 10 cm, find the area of the triangle.

Solution:            

Base of parallelogram = 15 cm

Altitude of parallelogram = 10 cm



Therefore Area of parallelogram = 15 × 10 cm2

                                            = 150 cm2

∆ ABD and parallelogram ABCD are on the same base AB.

Therefore of ∆ ABD = 1/2 the area of parallelogram ABCD

                           = 1/2 × 150 cm2

                           = 75 cm2