Question

e In the given figure , the lengths of arcs AB
and BE are
are in the ratio 3:2. If
ZAOB=96 find
1. ZBOC
ii. LABC
A
0
B​

Answer 1

Step-by-step explanation:

∡AOB=960

AB:BC=3:2

⇒∡AOB:∡BOC=3:2

⇒∡BOC960=23⇒∡BOC=32×960=640

Now, Δ"OBC is isosceles   [∵   OB=OC=r]

∴    ∡BOC+2∡OBC=1800

⇒∡OBC=2180−64=580

also Δ"AOB is isosceles  [because   OA=OB=r]

∴    ∡AOB+2∡OBA=1800

⇒∡OBA=2180−96=420

∴    ∡ABC=580+42