E is mid point of side BC of parallelogram ABCD such that CD:AD=1:2 then angle adc is=?
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Answer:
In given figure,
∠BPA=∠DAP
Because AP is a line which intersect two parallel line AD and BC
So, According given data
∠BAP=∠BAP
∠BPA=∠BAP
So, AB=BP
and AB∣∣CD
So, AD=BC
and P is mid point of BC
So, 2BP=BC
2BP=AD
AD=2AB
AB=CD
AD=2CD
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