E is the mid point of the median AD of AABC and BE is produced to
meet AC at F Show that AF =1/3 AC.
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Answer:
Draw DP||EF
In triangle ADP,E is the midpoint of AD and EF||DP
hence,Fis the midpoint of AP
In triangle FBC ,D is the midpoint of BC and DP||BF
hence,P is the midpoint of FC
Thus,AF=FP=PC
hence,AF=1/3AC
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