Question

e is the midpoint of the median area of triangle ABC and b b is produced to meet AC at F show that a is equals to one third AC​

Answer 1

hi mate

here is your answer

PLZ refer to the attachment.

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be brainly

Answer 2

$\underline{\mathfrak{\huge{Answer:}}}$

Refer to the Figure at first to understand each and every step clearly.

$\sf{Given:}$

E is midpoint of AD ( the median )

$\sf{To\:Prove :}$

$\tt{AF = \frac{1}{3}AC}$

$\sf{Proof:}$

$\underline{\sf{Constuction}}$: Draw DM || BF

In $\triangle$ADM :-

E is the midpoint of AD ( Given )

EF || DM ( by construction )

Thus, by the midpoint theorem, we can say that :-

F is the midpoint of AM

Therefore,

AF = FM ..(1)

In $\triangle$ BCF :-

D is the midpoint of BC ( Given )

DM || BF

Thus, by the midpoint theorem, we can say that :-

M is the midpoint of CF

Therefore,

FM = MC ...(2)

By (1) and (2), we can say that :-

AF = FM = MC

Now, we can also write :-

$\tt{AF = \frac{1}{3}AC}$

$\sf{Hence\:Proved!}$