Question

E length of a wire is doubled. By what factor does the resistance change

Answer 1

Explanation:

solution;

Let the resistance of the wire be R.

When the wire is doubled on itself and the process is repeated then -

The length of the wire reduces by 1/2, and the area increases by 2 times.

Thus, the resistance of the wire reduced by 1/4 times.

So, resistance = R/4

So, the total resistance of the wire when the resistors are arranged in parallel,

1/Rp = 1/(R/4) + 1/(R/4) + 1/(R/4) + 1/(R/4)

Rp = R/16

Thus, the resistance of the wire reduces by 16 times.

Answer 2

☆꧁༒ANSWER༒꧂☆

Formula of resistance →

$\boxed{R \: = ρ \frac{l}{A}}$

When length is increased two times , area will decrease twice .

Resistance is directly proportional to l while inversely proportional to A.

So , when length of wire will be doubled resistance will also become four times .

Thanks!❤️