E
Ly
1
I followed
2.
Anil talked about the
wrestlers,
3
I gave him my most
smile.
4
A little
helps in making friends,
was still a thief when I met Anll. And though only 15, I was an experienced and fairly successful hand.
Anil was watching a wrestling match when I approached him. He was about 25 a tall, lean fellow
and he looked easy-going, kind and simple enough for my purpose. I hadn't had much luck of late
and thought I might be able to get into the young man's confidence
"You look a bit of a wrestler yourself," I said. A little flatteryhelps in making friends.
"So do you," he replied, which put me off for a moment because at that time I was rather thin.
"Well," I sald modestly, "I do wrestle a bit."
"What's your name?" "Hari Singh," I lied. I took a new name every month. That kept me ahead of the
police and my former employers.
After this introduction, Anil talked about the well-olledwrestlers who were grunting, lifting and
throwing each other about. I didn't have much to say. Anll walked away.
I followed casually. "Hello again," he said. I gave him my most appealingsmile. "I want to work for
you," I said. "But I can't pay you." I thought that over for a minute. Perhaps I had misjudged my man.
I asked, "Can you feed me?"
"Can you cook?"
"I can cook," I lied again.
"If you can cook, then may be I can feed you."He took me to his room over the Jumna SweetShop and
told me I could sleep on the balcony. Butthe meall cooked that night must have been terrible
because Anil gave it to a stray dog and told me tobe off. But I just hung around, smiling in my
mostappealing way, and he couldn't help laughing.
A2. Complex factual Activity
1. Complete the following web-chart.
Qualities of Anil
Answers
Answer:
Before starting with the solution of this question, let us understand the concept.
\begin{gathered}\\\end{gathered}
Concept used:
cos also known as 'cosine' is the complimentary of sine as the name suggests.
So,
cos θ = sin (90 - θ)
\begin{gathered}\\\end{gathered}
Step-by-step explanation:
Applying this concept,
cos 72° can be written as sin (90° - 72°)
→ cos 72° = sin (90° - 72°)
⇒ cos 72° = sin 18°
\begin{gathered}\\\end{gathered}
Now, dividing by cos 72° on both sides,
\begin{gathered} \sf{ \dfrac{cos \: 72^{ \circ} }{cos \: 72 ^{ \circ} } = \dfrac{sin \: {18}^{ \circ} }{ cos \: 72 ^{ \circ} } } \\ \\ \end{gathered}
cos72
∘
cos72
∘
=
cos72
∘
sin18
∘
\begin{gathered} \implies \: \sf{ \dfrac{ \cancel{cos \: 72^{ \circ}} } { \cancel{cos \: 72 ^{ \circ}} } = \dfrac{sin \: {18}^{ \circ} }{ cos \: 72 ^{ \circ} } } \\ \\ \end{gathered}
⟹
cos72
∘
cos72
∘
=
cos72
∘
sin18
∘
\begin{gathered} \implies \sf{ 1= \dfrac{sin \: {18}^{ \circ} }{ cos \: 72 ^{ \circ} } } \\ \\ \end{gathered}
⟹1=
cos72
∘
sin18
∘
\begin{gathered} \therefore \: \boxed{ \bf{\dfrac{sin \: {18}^{ \circ} }{ cos \: 72 ^{ \circ} }} = 1} \\ \\ \end{gathered}
∴
cos72
∘
sin18
∘
=1
Answer:
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