Question

e moving with a uniform acceleration travels 24 metres and 64 metres in first to successive
of 4 seconds each. Its initial velocity is
​

Answer 1

Answer:

Explanation:

Distance travelled = 24m and 64m

Time = 4 seconds each

Thus,

The first interval of 4s the distance covered is 24m and in next 4s it covers distance of 64 m.

Let a be uniform acceleration and u be initial velocity.

From equation of motion s=ut +(1/2)at², we have for first interval,

24 = 4u+8a or

6 = u+2a ---(1)

For next interval, initial velocity is u+4a.

Therefore,

64=(u+4a)4+8a or

64=4u+24a or

16=u+6a ---(2)

Solving equations (1) and (2),

u=1m/s.