E. Numerical questions.
1. The frequency of a tuning fork is 256 Hz. Find its time period. (Ans. 0.0039 s)
2. The time period of a vibrating object is 0.025 s. Find its frequency. (Ans. 40 Hz)
Answers
Answered by
0
Answer:
answer 0.0039 of this question
Answered by
1
Explanation:
Sol 1. Frequency = 1 ÷ Time Period
∴ Time Period = 1 ÷ Frequency
= 1 ÷ 256
= 0.0039 s ←ANSWER
Sol 2. Frequency = 1 ÷ Time Period
= 1 ÷ 0.025
= 40 Hz ←ANSWER
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