Question

e of 22. A bullet of mass 50 g is moving with a velocity of
ich 500 m s-1. It penetrates 10 cm into a still target and
comes to rest. Calculate : (a) the kinetic energy
kg
possessed by the bullet, and (b) the average retarding
force offered by the target.
Ans. (a) 6250 J (b) 62500 N
J.​

Answer 1

Answer:

in the first part calculate kinetic energy using formula

K. E. =1/2mv²

note- mass to be taken in kg

1/2 *50/1000 *(500)²

=6250 J

using relation v²=u² + 2aS

calculate a (acceleration)

note -distance to be taken in metres

finally use F = ma

and obtain ur desired result

Explanation:

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Answer 2

Physics

mass = 50 g = 0,05 kg

velocity = 500 m/s²

distance = 10 cm = 0,1 meter

Kinetic : ____?

Force : ____?

Answer :

$KE = \frac{1}{2} m v^{2}$

KE = 1/2 × 0,05 × 500²

KE = 1/2 × 0,05 × 12500

KE = 0,05 × 12500

KE = 625 J

Force

W = F × s

625 = F × 0,1

625 / 0,1 = F

6250 N = F ✔