E pitch of a screw gauge is 1 mm and there are 100 divisions on the circular head. while measuring the thickness of a glass plate, the main scale reads 2 mm and the 76th division is in line with the base line. find the thickness of a glass plate. assume that the screw gauge is having a zero error of -0.05 mm. (4m)
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Answer:
Total Reading is 2.81 mm.
Explanation:
Given,
Pitch = 1mm
Circular Head Divisions = 100
Least Count = Pitch/C.H.D
= (1/100) mm
= 0.01 mm
Main Scale Reading = 2mm
Circular Head Reading = 76th div. Coincides,
(0.01*76) mm
= 0.76 mm
Observed Reading = (2+0.76) mm
= 2.76 mm
Zero Error = -0.05 mm
Total Reading = Observed Reading-(Zero Error with sign)
= 2.76-(-0.05) mm
= 2.76+0.05 mm
= 2.81 mm
Hope this helps.
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