Question

e) Prove that the bisector of two adjacent angles of a parallelogram intersect each other at
right angle.
The triangle so formed is to be used by a group housing society to construct an orphanage.
(1) For the triangle thus formed, name the type of triangle on the basis of the length of sides?
(ii)Also write down the measure of each angle of this triangle. (Non-anonymous question ) (15
Points) plz tell the 1 and second parts triangle formed and measure its urgent correct answer=BRAINLIEST​

Answer 1

Answer:

Step-by-step explanation:

Given : A parallelogram ABCD such that the bisectors of adjacent angles A and B intersect at P.  

To prove : ∠APB = 90°  

Proof : Since ABCD is a | | gm  

∴ AD  | | BC  

⇒ ∠A + ∠B = 180° [sum of consecutive interior angle]  

⇒ 1 / 2  ∠A  + 1 / 2  ∠B = 90°    

⇒ ∠1 + ∠2 = 90°  ---- (i)

[∵ AP is the bisector of ∠A and BP is the bisector of ∠B ]

∴ ∠1 = 1 / 2 ∠A and ∠2 = 1 / 2  ∠B]

Now, △APB , we have  

∠1  + ∠APB + ∠2 = 180°  [sum of three angles of a △]

⇒  90° + ∠APB + ∠2 = 180° [ ∵ ∠1 + ∠2 = 90° from (i)]

Hence,   ∠APB  =  90°  

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Answer 2

Answer:

The correct answer is 90°

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