e raise to x = x raise to y
show that dy/dx =logx-1/(logx)²
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Step-by-step explanation:
Take log on both sides, we get
x = y*logx
y = x/logx
dy/dx = [logx*1 - x*1/x]/[logx]² ( using division rule of differentiation, and that d/dx(x) = 1 and d/dx(logx) = 1/x)
dy/dx = (logx - 1)/(logx)²
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