Question

e raise to x = x raise to y
show that dy/dx =logx-1/(logx)²​

Answer 1

Step-by-step explanation:

Take log on both sides, we get

x = y*logx

y = x/logx

dy/dx = [logx*1 - x*1/x]/[logx]² ( using division rule of differentiation, and that d/dx(x) = 1 and d/dx(logx) = 1/x)

dy/dx = (logx - 1)/(logx)²