Math, asked by sanjitbasumatary, 10 months ago

e) Simplify
i) 1/
1+root 2

ii)7+root3/7-root3​

Answers

Answered by apriyadarshi751
0

Answer:

i>-1+\sqrt{2}

ii>52+14\sqrt{3}/46

Step-by-step explanation:

this question can be simplified by using the rationalize method-

which is 1/a-b=1/a-b*<a+b/a+b>

so the answer goes like this

i>     1/1+root 2

   = 1/1+root 2 *1-root 2/1-root 2

on dividing we get in numerator 1-\sqrt{2} and in denominator we get =(1+\sqrt{2})(1-\sqrt{2})

1-2=-1                                      <(a+b)(a-b)=a^{2}-b^{2}>

so the final answer is = -1+\sqrt{2}

ii)7+root3/7-root3

7+root3/7-root3    

so by rationalization we get -

7+root3/7-root3    *    7+root3/7+root3

7+\sqrt{3} whole square/     49-3    =   49+ 3+14\sqrt{3}/46

= 52+14\sqrt{3}/46

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thank buddy,

ADITYA PRIYADARSHI

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