Math, asked by sudakark10541, 6 months ago

e^(sin2x) find d2y/dx2

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Answered by animesharyan0011

Answer:

(2x cos 2x + 2xcos2x − 4x2 sin2x) − (2sin 2x + 4xcos2x) +. 2x sin 2x ... d2y dx2 + 2 dy dx. + 2y = 0. Method 1 y = e−x cosx dy dx ... Differentiate, we get: d2y dx2 + 2 dy.

Step-by-step explanation:

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e^(sin2x) find d2y/dx2​

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e^(sin2x) find d2y/dx2