[e(sinx + cosx)ds =
B. esinx + c
A. e cosx + c
D. -e'sinx + c
C. extanx + C
a
a
(=
A. ff(a + x)dx
c. ffla - x)dx
A.
B. [f(x - a)dx
D. ff(a.x)dx
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Answer:
B and D are the answers ieiw
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