Question

e smallest number by which 2560 must be multiplied so that the productis
a perfect cube.​

Answer 1

Answer:

25

Step-by-step explanation:

Prime factorisation of 2560 = $2^9 X 5$

Grouping them into triads for cube root,

$2^3 X 2^3X2^3X5$

Since, 5 is left without a triad, we need to fulfill the triad by multiplying $5^2=25$

Thus, 2560 is to be multiplied with 25 to form a number which is a perfect cube

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