Math, asked by rajchauhan398, 2 months ago

ए ट्रेन ट्रैवल्स 25% फर्स्ट डे नकार एयरपोर्ट ट्रैवल फ्रॉम a2b व्हिच इज 1 टू 1 मीटर अपार्ट स्टार्ट फ्रॉम द सेम प्वाइंट एंड एंड सेम टाइम​

Answers

Answered by saloni19748
1

Answer:

12.375 km/h

Step-by-step explanation:

let speed of car = x km/h

✓ speed of the train = x+x × 25/100 = 1.25x km/h

according to the problem

= 165/x - 165/1.25x = 40/60

= 165/5x = 2/3

= 10x = 495

x = 49.5

✓ difference in the speed of train and car

=1.25x - x

= 0.25x

= 0.25 × 49.5

= 12.375 km/h

hope it helps you

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