Question

(e) The graph above shows the results of the titration of the 20.mL sample of 0.10MHCl(aq) with 0.10MNaOH(aq) On the graph, draw an X to identify the location of the equivalence point of the titration.

Answer 1

Answer:

student was given the task of titrating a 20.mL sample of 0.10MHCl(aq) with 0.10MNaOH(aq). The HCl(aq) was placed in an Erlenmeyer flask. An equation for the reaction that occurs during the titration is given above.

How many moles of HCl are in the 20.mL sample of 0.10MHCl(aq)

Ok

Explanation:

Answer 2

Answer:

Equivalence point of the titration  $n_{B} = 0.002$

Explanation:

From the above question,

The graph shows the results of the titration of the 20.mL sample of 0.10MHCl(aq) with 0.10MNaOH(aq). On the graph, draw an X to identify the location of the equivalence point of the titration.

In the titration qualitative analysis of a compound using an analyte and titrant is done to determine the concentration of the analyte.

There are many types of titration such as acid-base titration, redox titration, volumetric titration, iodometric titration etc.

The technique used in potentiometric titration is similar to redox titration. in this titration, no indicator is used and potential is measured across the analyte.

The equivalence point of redox titration of potentiometric titration is symmetric at the equivalence point.

At this symmetric point, one mole of titrant and analyte completes the reaction.

The principle of potentiometers titration is based on the potential difference. when the analyte is used as an electrolyte and placed between the two electrodes the potential difference arises by adding titrant.

Given:

              20.mL sample of 0.10MHCl(aq) with 0.10MNaOH(aq)

               $\frac{0.10}{50} = n_{B} \\ n_{B} = 0.002$

For more related question : https://brainly.in/question/35232721

#SPJ5