Question

E
The intensity of
electric field (E) due
to a point charge q
at a distance r is​

Answer 1

Answer:

The intensity of electric field due to point charge Q at a distance of r =

$\frac{q}{4\pi \: e {r } ^{2} }$

Explanation:

consider a point charge Q placed at a point A. we interested in the electric field E at a point P at a distance r from Q.

Let us imagine a test charge q placed at P. The charge Q create a field E at P and this field exert a force F = qE on the charge q. But, from coulomb's law the force on charge q in the given situation is =

$\frac{qq}{4\pi \: e {r}^{2} }$

along AP.

NOTE :- In above expression Qq will be write in placed of qq.

NOW,

the electric field at P is =

$\frac{q}{4\pi \: e {r}^{2} }$