Question

(e) The length, breadth and height of a cuboid are 4
m, 3 m and 5 m. The length of the largest rod that
can be put in it will be:


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Answer 1

Answer:

5

$\sqrt{2}$

Step-by-step explanation:

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Answer 2

Given :

• Length = 4m
• Breadth = 3m
• Height = 5m

To Find :

• The length of the largest rod

Solution :

So, we've l = 4m, b = 3m, h = 5m

$Diagonal \: of \: cuboid =\sqrt{ {l}^{2} + {b}^{2} + {h}^{2} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{ {4}^{2} + {3}^{2} + {5}^{2} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{16 + 9 + 25} \\ \ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{50} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt[5]{2}$

Formula used :

Diagonal of cuboid = $\sqrt{ {l}^{2} + {b}^{2} + {h}^{2} }$