Question

(e) The melting points of three members A, B, C of a homologous series of hydrocarbons are -183°C
-138 Cand-130 Crespectively. Which would have lowest number of carbon atoms in its molecule? Why?
) Which two of the following belong to the same homologous series?
CH4O C2H6O2 C2H6O C2H6
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Answer 1

Answer:

bGsjusjdbebdb dhdh r d djh anisve s sbhsve