Question

E.
Time
The towns A and B are 80 km apart. A cyclist starts from A at 8am and cycles at 15km towards
Draw distance-time graph. What time does he reach B ? A motorist leaves the town But 10a.m.md
drives to A, arriving at 11:15 a.m. Plot the distance-time graph on the same axis and from it, state:
(1) his average speed,
(2) the distance from A when the cyclist and motorist meet.​

Answer 1

1 answer is 11 am he reach b

2 answer the distance from a when cyclist and motorist meet is 65

we can subtract 80 km - 15 km we can find answer

Answer 2

Answer:

Cyclist from town A reach town B at 1 pm 19 min past

Average speed of cyclist from town B is  1.067 km per min .

Step-by-step explanation:

Given as :

The distance between town A and B = 80 km

The speed of cyclist from town A = 15 km/h

The cyclist start from A at 8 am

∵ Time = $\dfrac{\textrm Distance}{\textrm speed}$

Or, Time =  $\dfrac{80}{15}$ hours

Or, time = 5.33 hours

So, Find taken by cyclist from A to reach town B = 5 hours 19 minutes

As he start from 8 am , so cyclist A reach town B at 8 am + 5 h 19 min

i.e cyclist A reach town B at 1 pm 19 min past

Again

From town B open at 10 a.m , and reach at 11 : 15 am

So, time taken to reach = 1 hour 15 min = 75 min

As distance between town = 80 km

So, The speed = $\dfrac{\textrm Distance}{\textrm time}$

or, Speed =  $\dfrac{80}{75}$ = 1.067 km per min

i.e speed = 64.02 km /h

Hence, cyclist from town A reach town B at 1 pm 19 min past

And Average speed of cyclist from town B is  1.067 km per min . Answer