Math, asked by ARSHITARORA, 8 months ago

e two sides of a triangle are 8 cm and 11 cm and the perimeter is 32 cm . Find the third side and the area of the triangle .

(2 Points)​

Answers

Answered by satishgoyal409
1

8√30 cm² = 43.82 cm²

Step-by-step explanation:

let \: 3rd \: side \:  =  \: x \: cm \\ perimeter = 32 \: cm \\ 8 + 11 + x = 32 \\ 19 + x = 32 \: \\ x = 32 - 19 \\ x = 13 \\ 3rd \: side \: = 13 \: cm \\ semi \: perimeter \:  =  \frac{32}{2}cm  \\ s = 16 \: cm \\ a = 8 \: cm \:  \\ b \:= \: 11 \: cm \:  \\ c = 13cm \\ by \: herons \: formula \\ area =  \sqrt{s \times s - a \times s - b \times s - c}  \\  =  \sqrt{16 \times 16 - 8 \times 16 - 11 \times 16 - 13}  \\  =  \sqrt{16 \times 8 \times 5 \times 3}  \\  = 8 \sqrt{2 \times 5 \times 3}  \\  = 8 \sqrt{30} = 43.82 cm² \\ area \: of \: triangle \:  = 8 \sqrt{30} \:   {cm}^{2} = 43.82 cm²

Similar questions
Math, 4 months ago