Question

(e) What three consecutive integers have
a sum of 21?
​

Answer 1

Answer:

answer

Step-by-step explanation:

What three consecutive integers have a sum of 21? Which means that the first number is 6, the second number is 6 + 1 and the third number is 6 + 2. Therefore, three consecutive integers that add up to 21 are 6, 7, and 8.

Answer 2

GivEn:

• $\sf Three \;consecutive \;integers \;have \;a \;sum\; 21.$

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To find:

• $\sf Value\; of\; those \;three \;consecutive \;integers.$

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SoluTion:

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$\sf Let \;the\; three \;consecutive \;numbers \;be \;x, \;(x + 1), \;(x + 2).$

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★ Now, According to question,

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$:\implies\sf x + (x + 1) + (x + 2) = 21$

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$:\implies\sf 3x + 3 = 21$

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$:\implies\sf 3( x + 1) = 21$

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$:\implies\sf x + 1 = \cancel{ \dfrac{21}{3}}$

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$:\implies\sf x = 7 - 1$

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$:\implies\bf \pink{x = 6}$

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$\sf Therefore, \;The\; Three \;numbers \;are,$

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• $\sf First \;number \;(x)$ = 6

• $\sf Second\; number\; (x + 1)$= 6 + 1 = 7

• $\sf Fourth \;number\; (x + 2)$ = 6 + 2 = 8

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$\therefore\sf Hence, \;Those \;three \;consecutive \;numbers\; are\; 6, \;7 \;and\; 8.$

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★ Verification:

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As per given Question,

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$\sf Three \;consecutive \;integers\; have\; a \;sum\; 21.$

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$\sf Therefore,$

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$\sf If \;we\; add \;up \;all \;three\; numbers \;then\; there\; sum\; must\; come\; 21.$

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$:\implies\sf 6 + 7 + 8$

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$:\implies\bf \purple{21}$

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$\therefore\sf We\; can \;say \;that \;our \;answer\; is \;correct.$