Question

(e) What will be the output of the following code:
def inter (p,t=2, rt=0.10)
re tum (p*t*rt)
print (in ter (6100, 1)
print (inter (5000, r=0.05)
print (inter(5000,3,0.12)
print (inter (t=4,p=5000)​

Answer 1

Explanation:

6100*1*0.10=61*10

5000*2*0.05=100*5

5000*3*0.12=150*12

5000*4*0.10=2000

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