Question

(e^x+1)y dy=(y+1)e^x dx
solve this​

Answer 1

Answer:

The given differential equation is (ex+1)ydy=(y+1)exdx

⇒(y+1)ydy=(ex+1)exdx; Integrating both sides

⇒y−log∣y+1∣=log(ex+1)+logk

⇒y=log∣(y+1)(ex+1)∣+logk

⇒(y+1)(ex+1)=cey