Question

e^x-e^2x/2x-sinx find the derivative​

Answer 1

➤ Answer in attachment!!!

Answer 2

Answer:

Let us consider this function of x as g(x)

Which is,

g(x) = e^x - e^2x / 2x - sin x

To find the derivative differentiating the right hand side by u/v rule.

We get,

g'(x) = (2x-sinx)(e^x-2e^2x)-(e^x-e^2x)(2-cosx)/(2x-sinx)^2

This will be the derivative of the given function.

Hope this helps you !