Math, asked by hs9013993, 1 month ago

e^x -x-1/x limit x to 0

Answers

Answered by mathdude500
1

\large\underline\blue{\bold{Given \:  Question :-  }}

\bf \:  ⟼ \bf \:\lim_{x\to\ \: 0}\dfrac{ {e}^{x}  - x  - 1}{x}

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 \:  \:  \:  \:  \:  \:   \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \: \huge \red{AηsωeR} ✍

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Method :-

Method :- L - H method

\bf \:  ⟼ \bf \:\lim_{x\to\ \: 0}\dfrac{ {e}^{x}  - x  - 1}{x}

\bf \:  ⟼ \bf \:\lim_{x\to\ \: 0}\dfrac{ \dfrac{d}{dx} ({e}^{x}  - x  - 1)}{\dfrac{d}{dx} x}

\bf \:  ⟼ \bf \:\lim_{x\to\ \: 0} \: ( {e}^{x}  - 1)

\bf\implies \: \:  = 1 - 1 = 0

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\large{\boxed{\boxed{\bf{Hence, \bf \:  ⟼ \bf \:\lim_{x\to\ \: 0}\dfrac{ {e}^{x}  - x  - 1}{x}  = 0}}}}

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