E = {x | x = (2n + 1), n € W, n<4}
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Answer:
On putting n=1,2,3,... in x=2n+1, we get
x=3,5,7,...
Therefore, in roster form the given set is
{3,5,7,...}
step by step explanation:
The given sets are:
A={x:x∈N}={1,2,3,4.....}
B={x:x=2n,n∈N}={2,4,6,8,10....}
C={x:x=2n−1,n∈N}={1,3,5,7,9.......}
D={x:x is a prime number}={2,3,5,7,11,13....}
∴ A∩B={1,2,3,4....}∩{2,4,6,8....}
={2,4,6,8....}
=B
Hence
A∩B=B
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