Math, asked by rajesh143jakal, 11 months ago

E={x:x is afactor of 24} F={x:x is a multiple of 3, x<30}

Answers

Answered by amitnrw
3

Given :   E={x:x is afactor of 24} F={x:x is a multiple of 3, x<30}

To Find : sets are disjoint or overlapping  

Solution:

Over lapping sets  - have atleast one common elements

Disjoint sets does not have any common element

E={x:x is afactor of 24}

24 = 1 * 24  

24 = 2 * 12

24 = 3 * 8

24 = 4 * 6

E= { 1 , 2 , 3 , 4 , 6 , 8 , 12 , 24 }

F={x:x is a multiple of 3, x<30}

F = {3 , 6 , 9 , 12 , 15 , 18 , 21 , 24 , 27 }

E ∩ F  = { 3 , 6 , 12 , 24 }

Over lapping sets

Learn more:

andB ( x:x is a dolution of x^2+6x+8=o )

https://brainly.in/question/17285000

B= {x:xe N, and 'x' is multiple of 8}C

https://brainly.in/question/14732925

Answered by Anonymous
4

(a) The collection of all the days in a week beginning with the letter ‘T’.

(b) The collection of all difficult questions in the chapter on sets.

(c) The collection of girls in your class.

(d) The collection of all rivers in India.

(e) The collection of all active teachers in the school.

(f) The collection of all integers more than -3.

(g) The collection of all beautiful flowers in the park

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