Question

E={x|x€N and x is a divisor of 12},
F={y|y€N and y is a divisor of 18}​

Answer 1

Answer:

Correct option is

A

E∪F={1,2,3,4,6,9,12,18}

Divisors of 12 are 1,2,3,4,6,12

∴E={1,2,3,4,6,12}

Again divisors of 18 are 1,2,3,6,9,18

∴F={1,2,3,6,9,18}

Now, union of sets is a set that contains elements that are present in any one of sets. Therefore, E∪F={1,2,3,4,6,9,12,18}