Question

e^x+y=xy then dy/dx=?​

Answer 1

Answer:

e'x + y = xy

e'x = y(x-1)

taking logarithm both side we have

ln x = ln y + ln (x-1)

ln y = ln x - ln (x-1)

ln y = ln (x/x-1)

y = x/x-1

dy/dx = ( (x-1)dx/dx-xd(x-1)/dx ) / (x-1)²

= x-1-x / (x-1)²

= -1/(x-1)²