Question

(e) x3 – 2x+y + 3xy2 - 6y​

Answer 1

Answer:

Given : x3−2x2y+3xy2−6y3

By taking x2 as common in the first two term and 3y2 as common in the second two term

x3−2x2y+3xy2−6y3=x2(x−2y)+3y2(x−2y)

So we get,

x3−2x2y+3xy2−6y3=(x−2y)(x2+3y2)

Step-by-step explanation: