e xpand (2b-1)wholepower3
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here is your answer bro
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Q-1. {2b-1}^3
solution:-
we know that,
{x-y}^3 = x^3 - y^3 - 3yx^2 + 3xy^2
so,
{2b-1}^3 = {2b}^3 - {1^3} - 3×1×{2b}^2 + 3×2b×1^2
= 8b^3 - 1 - 3×4b^2 + 6b
= 8b^3 - 1 - 12 b^2 + 6b
= 8b^3 - 12b^2 + 6b - 1
☺
please make me as brainlist
Q-1. {2b-1}^3
solution:-
we know that,
{x-y}^3 = x^3 - y^3 - 3yx^2 + 3xy^2
so,
{2b-1}^3 = {2b}^3 - {1^3} - 3×1×{2b}^2 + 3×2b×1^2
= 8b^3 - 1 - 3×4b^2 + 6b
= 8b^3 - 1 - 12 b^2 + 6b
= 8b^3 - 12b^2 + 6b - 1
☺
Answered by
0
Hope, this may help you
Mark as Brainliest, plz....
Mark as Brainliest, plz....
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