Question

e^xy'=2(x+1)y^2. ,y(0)=1/6​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

e^xy'=2(x+1)y^2. ,y(0)=1/6​, This holds for x=1,y=0

Step-by-step explanation:

From the above question, they have given

Given curve is $x+y=e xy$

On differentiating w.r.t x we get

$1+ dxdy​ =e xy {y+x dxdy​ }$

$dxdy​ = 1−xe xy ye xy −1​$

We have already seen a first order homogeneous linear differential equation, namely the simple growth and decay model

P s an antiderivative of −p ( t )

.As in previous examples, if we allow

A = 0

we get the constant solution  

y = 0

Here,  

⇒1−x(x+y)=0

This holds for x=1,y=0

As you might guess, a first order non-homogeneous linear differential equation has the form.

Not only is this closely related in form to the first order homogeneous linear equation, we can use what we know about solving homogeneous equations to solve the general linear equation.

For more related question : brainly.in/question/18722533

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