Chemistry, asked by Abid5321, 11 months ago

E° of three metals a, b, c are +0.44 v, +1.37 v and 1.35 v. Arrange the metals in increasing order of their reducing power

Answers

Answered by Anonymous
7

Answer:

Explanation:

Standard electrode potential helps to determine the oxidizing or reducing power of various metals.

More reducing power of metal means it can be easily reduced.

More negative the electrode potential,least is the oxidizing power or more is the reducing power.

The E° given here are +0.44,+1.37,-1.35.So, increasing order of reducing power of metals- b<a<c

Answered by sudiptamaji2007
2

Answer:

We know that, lower the standard electrode potential value, greater the reducing power. The standard electrode potential values are increasing in the order Li(−3.05V),K(−2.93V),Al(−1.66V),Ag(+0.80V),Au(+1.40V).

Therefore, the increasing order of reducing power is as follows:

Au<Ag<Al<K<Li.

Similar questions