E°1/2Cl2/Cl2 = + 1.36 V. The single electrode
potential of Pt/Cl2 (1 atm) Cl- (0.1 M) is
1)-1.36 V
2) + 1.36 V
3) +1.42 V
4) -1.42 V
Ti
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E°1/2Cl2/Cl2 = + 1.36 V. The single electrode
potential of Pt/Cl2 (1 atm) Cl- (0.1 M) is
1)-1.36 V
2) + 1.36 V
3) +1.42 V
4) -1.42 V
Ti
Answered by
1
Answer:
so the answer for this question is option 3
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