E1 E2 and E3 are the chemical equivalent of the three cells respectively. explain please
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the reactions are
Zn -------> Zn2+ + 2e
Cu2+ + 2e ------> Cu
Ecell=E-0.059/n*log([Zn2+]/[Cu2+])
or
Ecell=E+0.059/n*log([Cu2+]/[Zn2+])
since E is constant for all the 3 reactions therefore value of Ecell only depends on log([Cu2+]/[Zn2+])
for a
E1=E+0.059/2*log(0.1/1)
=E+0.059/2*(-1)
=E-0.059/2
for b
E2=E+0.059/2*log(1/1)
=E
for c
E3=E+0.059/2*log(1/0.1)
=E+0.059/2
on observation E3>E3>E1
Answered by
1
Answer:
option B is ur right answer ❣️❣️
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