Question

E1 E2 and E3 are the chemical equivalent of the three cells respectively. explain please

Answer 1

the reactions are

Zn -------> Zn2+ + 2e

Cu2+ + 2e ------> Cu

Ecell=E-0.059/n*log([Zn2+]/[Cu2+])

or

Ecell=E+0.059/n*log([Cu2+]/[Zn2+])

since E is constant for all the 3 reactions therefore value of Ecell only depends on log([Cu2+]/[Zn2+])

for a

E1=E+0.059/2*log(0.1/1)

=E+0.059/2*(-1)

=E-0.059/2

for b

E2=E+0.059/2*log(1/1)

=E

for c

E3=E+0.059/2*log(1/0.1)

=E+0.059/2

on observation E3>E3>E1

Answer 2

Answer:

option B is ur right answer ❣️❣️